What milliampere (mA) station would be used for an exposure with 0.6 seconds and 50 milliampere-seconds (mAs)?

To determine the correct milliampere (mA) station for an exposure given the time in seconds and the milliampere-seconds (mAs), the relationship between these values can be used. The formula linking mA, time (in seconds), and mAs is:

mAs = mA × time (seconds)

In this scenario, you've been provided with a time of 0.6 seconds and a total of 50 mAs. We need to isolate mA to find the correct value:

mA = mAs / time

Substituting the given values:

mA = 50 mAs / 0.6 seconds

Calculating this gives:

mA = 50 / 0.6 = approximately 83.33 mA

Since the mA station must be a whole number, we can round this to the nearest whole number, resulting in 83 mA. This calculation confirms that the correct milliampere station for this exposure is indeed 83 mA. This reflects the required tube current needed to produce the specified amount of radiation over the given time to achieve the necessary exposure.