If a generator has a capacity of 1000 milliampere (mA) and a technique of 20 milliampere-seconds (mAs), what is the shortest possible exposure time?

To find the shortest possible exposure time, you can use the relationship between current, time, and milliampere-seconds (mAs), which is expressed in the formula:

mAs = mA × time (seconds)

In this case, we have a generator with a capacity of 1000 milliampere (mA) and the technique set to 20 milliampere-seconds (mAs). To find the shortest exposure time, you can rearrange the formula to:

time = mAs / mA

By substituting the values into this formula:

time = 20 mAs / 1000 mA

This gives you:

time = 0.02 seconds

This indicates that the shortest possible exposure time, given the generator's output and the specified mAs, is indeed 0.02 seconds. This value aligns with practical applications in radiologic technology, where precise control of exposure times is essential for achieving optimal imaging results while minimizing patient exposure to radiation.